Question

c  program to check whether the given number is even or odd.

Answer 1

Program:
#include <stdio.h>
int main()
{
 int a;
 printf("Enter a: \n");
 scanf("%d", &a);
 /* logic */
 if (a % 2 == 0)
{
  printf("The given number is EVEN\n");
 }
 else
 {
  printf("The given number is ODD\n");
 }
 return 0;
}

Output:
Enter a: 2
The given number is EVEN

Example 1: If entered number is an even number
          Let value of 'a' entered is 4
          if(a%2==0) then a is an even number, else odd.
   i.e.  if(4%2==0) then 4 is an even number, else odd.
To check whether 4 is even or odd, we need to calculate (4%2).
/* % (modulus) implies remainder value. */
/* Therefore if the remainder obtained when 4 is divided by 2 is 0, then 4 is even. */
     4%2==0 is true
     Thus 4 is an even number.

Answer 2

#include<stdio.h>
void main()
{
int a;
printf("enter a value");
scanf9"%d",&a);
if(a/2==0)
printf("the given no'r is even")
else
printf(the no'r is odd");

Answer 3

 

#include<stdio.h>

main()

{

int r,n;

printf("\nEnter a positive number : ");

scanf("%d",&n);

r =n%2;

if(r==0)

printf("\nThe %d is an even number",n);

else

printf("\nThe %d is an odd number",n);

}