C program to generate the Fibonacci series.

Answer 1

Fibonacci series: Any number in the series is obtained by adding the previous two numbers of the series.

Let f(n) be n'th term.
f(0)=0;
f(1)=1;
f(n)=f(n-1)+f(n-2); (for n>=2)
Series is as follows
0
1
1 (1+0)
2 (1+1)
3 (1+2)
5 (2+3)
8 (3+5)
13 (5+8) and so on..

*******////PROGRAM:////**********

#include<stdio.h>
int main() {
 //array fib stores numbers of fibonacci series
 int i, fib[25];
 /////////initialized first element to 0
 fib[0] = 0;
 /////////initialized second element to 1
 fib[1] = 1;
 /////////loop to generate ten elements
 for (i = 2; i < 10; i++) {
  ///////// i'th element of series is equal to the sum of i-1'th element and i-2'th element.
  fib[i] = fib[i - 1] + fib[i - 2];
 }
 printf("The fibonacci series is as follows \n");
 /////////print all numbers in the series
 for (i = 0; i < 10; i++) {
  printf("%d \n", fib[i]);
 }
 return 0;
}

OUTPUT:
The fibonacci series is as follows
0
1
1
2
3
5
8
13
21
34

Comments

thanks a lot..!!!

Answer 2

#include<stdio.h>
void main()
{
int fib,num,n1,n2;
printf("enter num value");
scanf("%d",&num);
printf("enter n1,n2 values");
scanf("%d,%d",&n1,&n2);
for(i=0;i<num;i++)
{
fib=n1+n2;
n1=n2;
n2=fib;
}
}