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asked by Geek (15.3k points) 19 43 69 | 49 views

1 Answer

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#include<stdio.h>

#include<conio.h>

main(int argc, char *argv[])

{

Int x;

clrscr();

Printf(“\n Total number of arguments are %d \n ”, argc);

for(x=0; x<argc; x++)

Printf(“%s\t”, argv[x]);

getch();

return 0;

}

Output:

Total numbers of arguments are 4

C:\TC\C.EXE A B C

answered by Guru (39.1k points) 11 24 38

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