# Write a C program to find out the Fibonacci Series ?

#include

``````#include

void main()

{

int a=0,b=1,c=0,i,n;

clrscr();

printf(“enter the number of terms
``````

”);

``````printf(“%d
``````

%d”,a,b);

``````for(i=3;i&lt;=n;i++)

{

c=a+b;

printf(“%d
``````

”,c);

``````a=b;

b=c;

}

getch();

}

Output:

enter the number of terms

4

0

1

1

2``````

Fibonacci series: Any number in the series is obtained by adding the previous two numbers of the series.

Let f(n) be n’th term.

f(0)=0;

f(1)=1;

f(n)=f(n-1)+f(n-2); (for n>=2)

Series is as follows

011

(1+0)

2 (1+1)

3 (1+2)

5 (2+3)

8 (3+5)

13 (5+8)

21 (8+13)

34 (13+21)

…and so on

Program: to generate Fibonacci Series(10 terms)

#include

int main() {

//array fib stores numbers of fibonacci series

int i, fib[25];

//initialized first element to 0

fib[0] = 0;

//initialized second element to 1

fib[1] = 1;

//loop to generate ten elements

for (i = 2; i < 10; i++) {

//i’th element of series is equal to the sum of i-1’th element and i-2’th element.

fib[i] = fib[i - 1] + fib[i - 2];

}

printf("The fibonacci series is as follows
");

//print all numbers in the series

for (i = 0; i < 10; i++) {

printf("%d
", fib[i]);

}

return 0;

}

Output:

The fibonacci series is as follows

01123581

3

21

34

Explanation:

The first two elements are initialized to 0, 1 respectively. Other elements in the series are generated by looping and adding previous two numbes. These numbers are stored in an array and ten elements of the series are printed as output.